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How do I print all arguments submitted on a command line from a bash script?

Last Updated on Friday, 01 April 2011 18:22

Question:

How do I print all arguments submitted on a command line from a bash script?

Answer:

There are couple ways how to print bash arguments from a script. Try some scripts below to name just few.

In this first script example you just print all arguments:

 #!/bin/bash 
echo $@ 

If you intend to do something with your arguments within a script you can try somethign simple as the following script:

 #!/bin/bash 
 for i; do 
    echo $i 
 done

Next we have some script which are doing the same as the previous bash script but employ different approach:

 #/bin/bash 
 for i in $*; do 
   echo $i 
 done

Let's print all bash arguments using shift:

 #!/bin/bash 
 
while (( "$#" )); do 
  echo $1 
  shift 
done 
 

Or we can do something obscure like this to print all bash arguments:

 #/bin/bash 
 
# store arguments in a special array 
args=("$@") 
# get number of elements 
ELEMENTS=${#args[@]} 
 
# echo each element in array  
# for loop 
for (( i=0;i<$ELEMENTS;i++)); do 
    echo ${args[${i}]} 
done 

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