Network Bits: 16
Network bits available ( x ):10xxxxxx xxxxxxxx hosts hosts this leave us with 14 bits designated to the number of networks. Since there are two possible bits to play with ( 1 or 0 ) the range of network is 2^14 = 16384. We need to subtract broadcast and network ID and the number of networks available is 16382.
RANGE: 10000000 – 10111111 -> 128 -191
Hosts:The number of available hosts can be calculated from a remaining 16 host bits. 2^16 = 65,536 subtract network ID and broadcast adress and this gives us 65,534 hosts available for CLASS B Network.